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Solid Mechanics II
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Solid Mechanics II
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C4: Torsion
4.1 Statically Indeterminate Analysis with Torque
- Theory - Example - Question 1 - Question 2
4.2 Thin-Walled Tubes with Closed Cross-Sections
- Theory - Example - Question 1 - Question 2

C4.2 Thin-Walled Tubes with Closed Cross-Sections

Thin-walled members are often used in lightweight structures to minimise material and yet provide sufficient strength. Depending on the structure, thin-walled members are often subjected to torque as well:


Example of aircraft-wing (thin-walled member) subjected to torque due to uneven pressure distribution along the wing

C4.2 Thin-Walled Tubes with Closed Cross-Sections

Thin-walled members are often used in lightweight structures to minimise material and yet provide sufficient strength. Depending on the structure, thin-walled members are often subjected to torque as well:


Example of aircraft-wing (thin-walled member) subjected to torque due to uneven pressure distribution along the wing

Therefore it is important for us to know how to analyse the stresses on such structures due to torque loadings. The theory presented in this section is based on the assumption that:

  1. the cross-sections are closed (no open-ends), and
  2. thin enough such that the shear stress is even throughout the thickness.

We’ll be looking at the shear stress and angle of twist due to the torque loading.

Average shear stress

The average shear stress for torque-loaded thin-walled tubes can be calculated using:


Formula for average shear stress due to torque
Note:
  • T is the torque applied (units: Nm)
  • t is the thickness of the point where we are calculating τavg (units: m or mm)
  • Am is the mean area enclosed within the boundary of the cross-section, measured along the centreline of the thickness (units: m2 or mm2)

An example of the Am calculation is shown below:

Example of mean enclosed area calculation

Angle of twist

The angle of twist for torque-loaded thin-walled tubes can be calculated using:


Formula for angle of twist due to torque
Note:
  • G is the shear modulus (units: GPa)
  • L is the length of the beam. Often, questions ask for the angle of twist per unit length, in which you can shift L to get Φ/L
  • ∮ ds is the perimeter of the enclosed area. For ∮ ds/t, each length of the perimeter is to be divided by its respective thickness (we’ll show you this in the example).

Let’s look at an example now.

Therefore it is important for us to know how to analyse the stresses on such structures due to torque loadings. The theory presented in this section is based on the assumption that:

  1. the cross-sections are closed (no open-ends), and
  2. thin enough such that the shear stress is even throughout the thickness.

We’ll be looking at the shear stress and angle of twist due to the torque loading.

Average shear stress

The average shear stress for torque-loaded thin-walled tubes can be calculated using:


Formula for average shear stress due to torque
Note:
  • T is the torque applied (units: Nm)
  • t is the thickness of the point where we are calculating τavg (units: m or mm)
  • Am is the mean area enclosed within the boundary of the cross-section, measured along the centreline of the thickness (units: m2 or mm2)

An example of the Am calculation is shown below:

Example of mean enclosed area calculation

Angle of twist

The angle of twist for torque-loaded thin-walled tubes can be calculated using:


Formula for angle of twist due to torque
Note:
  • G is the shear modulus (units: GPa)
  • L is the length of the beam. Often, questions ask for the angle of twist per unit length, in which you can shift L to get Φ/L
  • ∮ ds is the perimeter of the enclosed area. For ∮ ds/t, each length of the perimeter is to be divided by its respective thickness (we’ll show you this in the example).

Let’s look at an example now.

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